2(x-5)+x^2=x(x+2)-10

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Solution for 2(x-5)+x^2=x(x+2)-10 equation:


Simplifying
2(x + -5) + x2 = x(x + 2) + -10

Reorder the terms:
2(-5 + x) + x2 = x(x + 2) + -10
(-5 * 2 + x * 2) + x2 = x(x + 2) + -10
(-10 + 2x) + x2 = x(x + 2) + -10

Reorder the terms:
-10 + 2x + x2 = x(2 + x) + -10
-10 + 2x + x2 = (2 * x + x * x) + -10
-10 + 2x + x2 = (2x + x2) + -10

Reorder the terms:
-10 + 2x + x2 = -10 + 2x + x2

Add '10' to each side of the equation.
-10 + 2x + 10 + x2 = -10 + 2x + 10 + x2

Reorder the terms:
-10 + 10 + 2x + x2 = -10 + 2x + 10 + x2

Combine like terms: -10 + 10 = 0
0 + 2x + x2 = -10 + 2x + 10 + x2
2x + x2 = -10 + 2x + 10 + x2

Reorder the terms:
2x + x2 = -10 + 10 + 2x + x2

Combine like terms: -10 + 10 = 0
2x + x2 = 0 + 2x + x2
2x + x2 = 2x + x2

Add '-2x' to each side of the equation.
2x + -2x + x2 = 2x + -2x + x2

Combine like terms: 2x + -2x = 0
0 + x2 = 2x + -2x + x2
x2 = 2x + -2x + x2

Combine like terms: 2x + -2x = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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